java – 在块中迭代一个hashmap’
发布时间:2020-05-25 01:14:55 所属栏目:Java 来源:互联网
导读:我需要遍历一个包含5000个项目的hashmap,但是在迭代了第500个项目之后我需要进行一次睡眠然后继续下一个500项目.这是从 here偷来的例子.任何帮助将不胜感激. import java.util.HashMap;import java.util.Map;public class HashMapExample { public static voi
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我需要遍历一个包含5000个项目的hashmap,但是在迭代了第500个项目之后我需要进行一次睡眠然后继续下一个500项目.这是从 here偷来的例子.任何帮助将不胜感激. import java.util.HashMap;
import java.util.Map;
public class HashMapExample {
public static void main(String[] args) {
Map vehicles = new HashMap();
// Add some vehicles.
vehicles.put("BMW",5);
vehicles.put("Mercedes",3);
vehicles.put("Audi",4);
vehicles.put("Ford",10);
// add total of 5000 vehicles
System.out.println("Total vehicles: " + vehicles.size());
// Iterate over all vehicles,using the keySet method.
// here are would like to do a sleep iterating through 500 keys
for(String key: vehicles.keySet())
System.out.println(key + " - " + vehicles.get(key));
System.out.println();
String searchKey = "Audi";
if(vehicles.containsKey(searchKey))
System.out.println("Found total " + vehicles.get(searchKey) + " "
+ searchKey + " cars!n");
// Clear all values.
vehicles.clear();
// Equals to zero.
System.out.println("After clear operation,size: " + vehicles.size());
}
}
解决方法只需要一个计数器变量来跟踪到目前为止的迭代次数:int cnt = 0;
for(String key: vehicles.keySet()) {
System.out.println(key + " - " + vehicles.get(key));
if (++cnt % 500 == 0) {
Thread.sleep(sleepTime); // throws InterruptedException; needs to be handled.
}
}
请注意,如果您想在循环中同时使用键和值,则最好迭代映射的entrySet(): for(Map.Entry<String,Integer> entry: vehicles.entrySet()) {
String key = entry.getKey();
Integer value = entry.getValue();
// ...
}
另外:不要使用原始类型: Map<String,Integer> vehicles = new HashMap<>(); (编辑:安卓应用网) 【声明】本站内容均来自网络,其相关言论仅代表作者个人观点,不代表本站立场。若无意侵犯到您的权利,请及时与联系站长删除相关内容! |
