java – 用名称替换小数1到10(“one”,“two”..)
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我试图取一个字符串然后返回一个数字1到10的字符串替换为这些数字的单词.例如:
应成为:
所以我这样做了: import org.apache.commons.lang3.StringUtils;
String[] numbers = new String[] {"1","2","3","4","5","6","7","8","9","10"};
String[] words = new String[]{"one","two","three","four","five","six","seven","eight","nine","ten"};
System.out.print(StringUtils.replaceEach(phrase,numbers,words));
结果如下:
所以我尝试了一种蛮力方式,我确信可以通过正则表达式或更优雅的字符串操作来改进: public class StringReplace {
public static void main(String[] args) {
String phrase = "I won 7 of the 10 games and received 30 dollars.";
String[] sentenceWords = phrase.split(" ");
StringBuilder sb = new StringBuilder();
for (String s: sentenceWords) {
if (isNumeric(s)) {
sb.append(switchOutText(s));
}
else {
sb.append(s);
}
sb.append(" ");
}
System.out.print(sb.toString());
}
public static String switchOutText(String s) {
if (s.equals("1"))
return "one";
else if (s.equals("2"))
return "two";
else if (s.equals("3"))
return "three";
else if (s.equals("4"))
return "four";
else if (s.equals("5"))
return "fivee";
else if (s.equals("6"))
return "six";
else if (s.equals("7"))
return "seven";
else if (s.equals("8"))
return "eight";
else if (s.equals("9"))
return "nine";
else if (s.equals("10"))
return "ten";
else
return s;
}
public static boolean isNumeric(String s) {
try {
int i = Integer.parseInt(s);
}
catch(NumberFormatException nfe) {
return false;
}
return true;
}
}
有没有更好的方法?特别感兴趣的是正则表达式的建议. 解决方法此方法使用正则表达式匹配由非数字(或开始或结束字符)包围的目标数字:String[] words = { "one","ten" };
String phrase = "I won 7 of the 10 games and received 30 dollars.";
for (int i = 1; i <= 10; i++) {
String pattern = "(^|D)" + i + "(D|$)";
phrase = phrase.replaceAll(pattern,"$1" + words[i - 1] + "$2");
}
System.out.println(phrase);
这打印:
如果数字是句子中的第一个或最后一个单词,它也会处理.例如:
正确地翻译成
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