双向链表实现java代码
发布时间:2020-05-28 16:15:10 所属栏目:Java 来源:互联网
导读:双向链表实现java代码
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下面是脚本之家 jb51.cc 通过网络收集整理的代码片段。 脚本之家小编现在分享给大家,也给大家做个参考。 /*
* To change this template,choose Tools | Templates
* and open the template in the editor.
*/
package linkedlisttest;
/**
*
* @author Lindily
*/
public class LinkedList<E> {
int size = 0;
Node<E> head = new Node(null,null,null);
public LinkedList() {
head.next = head.previous = head;
}
public void add(E node) {
//核心 循环双向链表
Node<E> newNode = new Node(head.previous,node,head); //新节点的prev指向头结点的prev 新节点的next指向头结点
newNode.previous.next = newNode; //调整,新节点的前一个的后一个
newNode.next.previous = newNode; //调整,新节点的后一个的前一个
size++;
}
public Node get(int index) {
if (index < 0 || index >= size) {
throw new IndexOutOfBoundsException("Index:" + index + ",size:" + size);
}
Node node = head;
if (index < (size >> 1)) { //index转为二进制带符号向右移动一个bit,相当于index/2
for (int i = 0; i <= index; i++) { //head是哑元,i<=index当index=0时,返回head.next
node = node.next; //对头结点进行迭代
}
}else{
for(int i=size;i>index;i--){
node=node.previous;
}
}
return node;
}
public int size() {
return size;
}
public static void main(String[] args) {
LinkedList list = new LinkedList();
list.add(1);
list.add(2);
list.add(3);
for (int i = 0; i < list.size; i++) {
System.out.println(list.get(i).node);
}
}
}
class Node<E> {
E node;
Node<E> next;
Node<E> previous;
public Node(Node<E> previous,E node,Node<E> next) {
this.node = node;
this.next = next;
this.previous = previous;
}
}
/*
* To change this template,choose Tools | Templates
* and open the template in the editor.
*/
package linkedlisttest;
/**
*
* @author Lindily
*/
public class SingleLinkedList<T> {
int size = 0;
Node<T> head,tail;
public SingleLinkedList() {
head = tail = null;
}
public void add(T node) {
if (size == 0) {
head = tail = new Node<T>(node,null);
} else {
tail.next = new Node<T>(node,null);
tail = tail.next;
}
size++;
}
public Node<T> get(int index) {
if (index < 0 || index >= size) {
throw new IndexOutOfBoundsException("Index:" + index + ",size:" + size);
}
Node<T> node = head;
for (int i = 0; i < index; i++) { //当index=0时,i不小于index(零不小于零),于是直接return头结点,与linkedList不同,head不是哑元
node = node.next; //对头结点进行迭代
}
return node;
}
public int size(){
return size;
}
public static void main(String[] args){
SingleLinkedList list=new SingleLinkedList();
list.add(1);
list.add(2);
list.add(3);
for(int i=0;i<list.size();i++){
System.out.println(list.get(i).node);
}
}
}
class Node<T> {
T node;
Node<T> next;
public Node(T node,Node next) {
this.node = node;
this.next = next;
}
}
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