java – nextDouble()在输入double时抛出异常
发布时间:2020-05-28 21:47:14 所属栏目:Java 来源:互联网
导读:import java.util.*;class Averager{ public static double unlimited() { int count = 0; double sum = 0; Scanner scan = new Scanner(System.in); while(scan.hasNex
import java.util.*;
class Averager
{
public static double unlimited()
{
int count = 0;
double sum = 0;
Scanner scan = new Scanner(System.in);
while(scan.hasNext())
{
double d = scan.nextDouble();
sum += d;
count++;
}
double ave = sum/count;
return ave;
}
public static void main(String[] args) {
System.out.println(unlimited()+"n");
}
}
使用整数时没有错误,但如果我使用带有点的数字则会出现错误. $javac Averager.java; java Averager
0.5
Exception in thread "main" java.util.InputMismatchException
at java.util.Scanner.throwFor(Scanner.java:840)
at java.util.Scanner.next(Scanner.java:1461)
at java.util.Scanner.nextDouble(Scanner.java:2387)
at Averager.unlimited(Averager.java:12)
at Averager.main(Averager.java:21)
据我所知,0.5应该用双倍覆盖.如果不是,请有人纠正我. 解决方法它可能依赖于语言环境.在瑞典,十进制数字例如写为0.5.改变你的代码,以便例如: Scanner scan = new Scanner(System.in); scan.useLocale(Locale.US); (编辑:安卓应用网) 【声明】本站内容均来自网络,其相关言论仅代表作者个人观点,不代表本站立场。若无意侵犯到您的权利,请及时与联系站长删除相关内容! |
