Freemarker如何生成树形导航菜单(递归)
发布时间:2020-05-29 16:52:43 所属栏目:Java 来源:互联网
导读:很多导航菜单是树形的,即一级一级往下分,这样的结构固然需要用递归来处理。
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很多导航菜单是树形的,即一级一级往下分,这样的结构固然需要用递归来处理。 对于Freemarker 来说,宏就相当于函数,其定义了签名及参数列表。 所以在freemarker页面应这样写:
<#macro menuTree menus>
<#if menus?? && menus?size gt 0>
<#list menus as menu>
<tr>
<td>
<input type="checkbox" name="ids" value="${menu.id}" />
</td>
<td>
<span title="${menu.name!}" style="margin-left: ${menu.leaf * 30}px;[#if menu.leaf == 0] color: #000000;[/#if]">
${menu.menuName!}
</span>
</td>
<td>
${menu.url!}
</td>
<td>
${menu.permissionText!}
</td>
<td>
${menu.sortNo!}
</td>
<td>
<a href="edit.jhtml?id=${menu.id}" rel="external nofollow" >[编辑]</a>
</td>
</tr>
<#if menu.menuBeans?? && menu.menuBeans?size gt 0>
<@menuTree menus = menu.menuBeans/>
</#if>
</#list>
</#if>
</#macro>
<!-- 调用宏 生成递归树 -->
<@menuTree menus = dto />
后台数据:
[
{
"id": 1,"enable": true,"remark": null,"createBy": 1,"createTime": 1503546411000,"updateBy": 1,"updateTime": 1503546415000,"keyword": null,"menuName": "系统管理","menuType": 1,"parentId": null,"iconcls": null,"url": null,"expand": null,"sortNo": null,"permission": null,"moduleId": 1,"parentName": null,"leaf": 0,"typeName": null,"permissionText": null,"menuBeans": [
{
"id": 7,"menuName": "模块管理","parentId": 1,"url": "/module/list","leaf": 1,"menuBeans": null
},{
"id": 3,"menuName": "菜单管理","url": "/menu/list","permission": "admin:add","menuBeans": null
}
]
},{
"id": 2,"menuName": "用户管理","menuBeans": [
{
"id": 9,"menuName": "供应商管理","parentId": 2,{
"id": 8,"menuName": "部门管理",{
"id": 6,"menuName": "权限管理","url": "/user/list-6",{
"id": 5,"menuName": "角色管理","url": "/user/list-5",{
"id": 4,"menuName": "分销商管理","url": "/user/add-4",{
"id": 10,"menuName": "员工管理","menuBeans": null
}
]
}
]
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