如何在JAVA中解析此JSON响应
发布时间:2020-05-30 18:15:25 所属栏目:Java 来源:互联网
导读:我想解析这些Json响应: {MyResponse: { count: 3, listTsm: [{ id: b90c6218-73c8-30bd-b532-5ccf435da766, simpleid: 1, name: vignesh1 }, { id: b9
|
我想解析这些Json响应: {
"MyResponse": {
"count": 3,"listTsm": [{
"id": "b90c6218-73c8-30bd-b532-5ccf435da766","simpleid": 1,"name": "vignesh1"
},{
"id": "b90c6218-73c8-30bd-b532-5ccf435da766","simpleid": 2,"name": "vignesh2"
},"simpleid": 3,"name": "vignesh3"
}]
}
}
我尝试使用SIMPLE JSON解析器,但这对我不起作用: Object obj = parser.parse(resp);
JSONObject jsonObject = (JSONObject) obj;
JSONArray response = (JSONArray) jsonObject.get("MyResponse");
//JSONArray arr=new JSONArray(yourJSONresponse);
ArrayList<String> list = new ArrayList<String>();
for(int i=0; i<response.size(); i++){
list.add(response.get(i)("name"));
}
解决方法public static void main(String[] args) throws JSONException {
String jsonString = "{" +
" "MyResponse": {" +
" "count": 3," +
" "listTsm": [{" +
" "id": "b90c6218-73c8-30bd-b532-5ccf435da766"," +
" "simpleid": 1," +
" "name": "vignesh1"" +
" }," +
" {" +
" "id": "b90c6218-73c8-30bd-b532-5ccf435da766"," +
" "simpleid": 2," +
" "name": "vignesh2"" +
" }," +
" "simpleid": 3," +
" "name": "vignesh3"" +
" }]" +
" }" +
"}";
JSONObject jsonObject = new JSONObject(jsonString);
JSONObject myResponse = jsonObject.getJSONObject("MyResponse");
JSONArray tsmresponse = (JSONArray) myResponse.get("listTsm");
ArrayList<String> list = new ArrayList<String>();
for(int i=0; i<tsmresponse.length(); i++){
list.add(tsmresponse.getJSONObject(i).getString("name"));
}
System.out.println(list);
}
}
输出: [vignesh1,vignesh2,vignesh3] 评论:我没有添加验证 [编辑] 加载json String的其他方法 JSONObject obj= new JSONObject();
JSONObject jsonObject = obj.fromObject(jsonString);
.... (编辑:安卓应用网) 【声明】本站内容均来自网络,其相关言论仅代表作者个人观点,不代表本站立场。若无意侵犯到您的权利,请及时与联系站长删除相关内容! |
