一个读取远程文件的PHP函数
发布时间:2020-05-25 07:11:46 所属栏目:PHP 来源:互联网
导读:一个读取远程文件的PHP函数
下面是脚本之家 jb51.cc 通过网络收集整理的代码片段。 脚本之家小编现在分享给大家,也给大家做个参考。 function urlfopen($url,$limit = 0,$post = '',$cookie = '',$bysocket = FALSE,$ip = '',$timeout = 15,$block = TRUE,$encodetype = 'URLENCODE') { $return = ''; $matches = parse_url($url); $host = $matches['host']; $path = $matches['path'] ? $matches['path'].(isset($matches['query']) ? '?'.$matches['query'] : '') : '/'; $port = !empty($matches['port']) ? $matches['port'] : 80; if($post) { $out = "POST $path HTTP/1.0rn"; $out .= "Accept: */*rn"; $out .= "Accept-Language: zh-cnrn"; $boundary = $encodetype == 'URLENCODE' ? '' : ';'.substr($post,trim(strpos($post,"n"))); $out .= $encodetype == 'URLENCODE' ? "Content-Type: application/x-www-form-urlencodedrn" : "Content-Type: multipart/form-data$boundaryrn"; $out .= "User-Agent: $_SERVER[HTTP_USER_AGENT]rn"; $out .= "Host: $hostrn"; $out .= 'Content-Length: '.strlen($post)."rn"; $out .= "Connection: Closern"; $out .= "Cache-Control: no-cachern"; $out .= "Cookie: $cookiernrn"; $out .= $post; } else { $out = "GET $path HTTP/1.0rn"; $out .= "Accept: */*rn"; $out .= "Accept-Language: zh-cnrn"; $out .= "User-Agent: $_SERVER[HTTP_USER_AGENT]rn"; $out .= "Host: $hostrn"; $out .= "Referer: rn"; $out .= "Connection: Closern"; $out .= "Cookie: $cookiernrn"; } $fp = @fsockopen(($ip ? $ip : $host),$port,$errno,$errstr,$timeout); if(!$fp) { return ''; } else { stream_set_blocking($fp,$block); stream_set_timeout($fp,$timeout); @fwrite($fp,$out); $status = stream_get_meta_data($fp); if(!$status['timed_out']) { while (!feof($fp)) { if(($header = @fgets($fp)) && ($header == "rn" || $header == "n")) { break; } } $stop = false; while(!feof($fp) && !$stop) { $data = fread($fp,($limit == 0 || $limit > 8192 ? 8192 : $limit)); $return .= $data; if($limit) { $limit -= strlen($data); $stop = $limit <= 0; } } } @fclose($fp); return $return; } } 以上是脚本之家(jb51.cc)为你收集整理的全部代码内容,希望文章能够帮你解决所遇到的程序开发问题。 如果觉得脚本之家网站内容还不错,欢迎将脚本之家网站推荐给程序员好友。 (编辑:安卓应用网) 【声明】本站内容均来自网络,其相关言论仅代表作者个人观点,不代表本站立场。若无意侵犯到您的权利,请及时与联系站长删除相关内容! |