php – 将未定义的参数数转发给另一个函数

我将用一个接受任意数量函数的简单函数来解释这个问题

function abc() {
   $args = func_get_args();
   //Now lets use the first parameter in something...... In this case a simple echo
   echo $args[0];
   //Lets remove this first parameter 
   unset($args[0]); 

   //Now I want to send the remaining arguments to different function,in the same way as it received
   .. . ...... BUT NO IDEA HOW TO . ..................

   //tried doing something like this,for a work around
   $newargs = implode(",",$args); 
   //Call Another Function
   anotherFUnction($newargs); //This function is however a constructor function of a class
   // ^ This is regarded as one arguments,not mutliple arguments....

}

我希望现在的问题很清楚,这种情况的解决方法是什么？

更新

我忘了提到我调用的下一个函数是另一个类的构造函数类.
就像是

$newclass = new class($newarguments);

使用call_user_func_array,但不要破坏args,只需将剩余的args数组传递给call_user_func_array

call_user_func_array('anotherFunction',$args);

用于创建对象

用途：ReflectionClass::newInstanceArgs

$refClass = new ReflectionClass('yourClassName');
$obj = $refClass->newInstanceArgs($yourConstructorArgs);

或者：ReflectionClass::newinstance

$refClass = new ReflectionClass('yourClassName');
$obj = call_user_func_array(array($refClass,'newInstance'),$yourConstructorArgs);

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