发送php响应给ajax
发布时间:2020-05-31 00:37:22 所属栏目:PHP 来源:互联网
导读:好的,我有一个 PHP脚本,结尾如此: if ($success){ $result = array(success = true);}else{ $result = array(success = false, message = Something happened); header($_SERVER[SERVER_PROTOCOL]
好的,我有一个 PHP脚本,结尾如此: if ($success) { $result = array('success' => true); } else { $result = array('success' => false,'message' => 'Something happened'); header($_SERVER['SERVER_PROTOCOL'] . ' 500 Internal Server Error',true,500); } echo json_encode($result); 还有一些jquery,我计划在我的脚本运行时提醒我. jQuery(document).ready(function() { $.ajax({ url: './contactengine.php',type: 'GET',dataType: 'JSON',success: function(response) { alert("GOOD"); },error: function() { alert("BAD"); } }); }); 编辑来源 <?php if ($success){ $result = array("status" => "1"); echo json_encode($result); } else{ print "<meta http-equiv="refresh" content="0;URL=/404.html">"; } ?> <script> jQuery(document).ready(function() { $.ajax({ type: 'GET',url: 'Thatscriptsomething.php',cache: 'false',dataType: 'json',success: function(response) { if(response.status == "1") { alert("we having a working script"); } else { alert("Oops,script is a no go"); } } }); }); </script> (编辑:安卓应用网) 【声明】本站内容均来自网络,其相关言论仅代表作者个人观点,不代表本站立场。若无意侵犯到您的权利,请及时与联系站长删除相关内容! |