Django clean方法在POST上抛出KeyError
发布时间:2020-05-23 10:03:05 所属栏目:Python 来源:互联网
导读:当我尝试提交表单时,我会收到一个“密码”的KeyError. 跟踪: Request Method: POSTRequest URL: http://localhost:8000/register/Django Version: 1.2.1Python Version: 2.7.0Installed Applications:[django.contrib.auth, djang
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当我尝试提交表单时,我会收到一个“密码”的KeyError. 跟踪: Request Method: POST
Request URL: http://localhost:8000/register/
Django Version: 1.2.1
Python Version: 2.7.0
Installed Applications:
['django.contrib.auth','django.contrib.contenttypes','django.contrib.sessions','djangoproject1.authentication']
Installed Middleware:
('django.middleware.common.CommonMiddleware','django.contrib.sessions.middleware.SessionMiddleware','django.contrib.auth.middleware.AuthenticationMiddleware')
Traceback:
File "C:Python27libsite-packagesdjangocorehandlersbase.py" in get_response
100. response = callback(request,*callback_args,**callback_kwargs)
File "C:Usersjec23My Java Projectsdjangoproject1srcdjangoproject1authenticationviews.py" in register
20. if rf.is_valid() and pf.is_valid():
File "C:Python27libsite-packagesdjangoformsforms.py" in is_valid
121. return self.is_bound and not bool(self.errors)
File "C:Python27libsite-packagesdjangoformsforms.py" in _get_errors
112. self.full_clean()
File "C:Python27libsite-packagesdjangoformsforms.py" in full_clean
268. self._clean_form()
File "C:Python27libsite-packagesdjangoformsforms.py" in _clean_form
296. self.cleaned_data = self.clean()
File "C:Usersjec23My Java Projectsdjangoproject1srcdjangoproject1authenticationforms.py" in clean
16. if self.cleaned_data['cpassword']!=self.cleaned_data['password']:
Exception Type: KeyError at /register/
Exception Value: 'password'
观点: def register(request):
if request.method == 'POST':
rf = forms.RegisterForm(request.POST)
pf = forms.ProfileForm(request.POST)
if rf.is_valid() and pf.is_valid():
newuser = User(username=rf.cleaned_data['username'],email=rf.cleaned_data['email'])
newuser.set_password(rf.cleaned_data['password'])
newuser.save()
profile = pf.save(commit=False)
profile.user = newuser
profile.save()
return HttpResponseRedirect("/register-success/")
else:
return render_to_response("authentication/index.html",{'form1': rf,'form2':pf})
else:
return main(request)
形式: class RegisterForm(forms.Form):
username = forms.CharField(min_length=6,max_length=15)
password = forms.CharField(min_length=6,max_length=15,widget = forms.PasswordInput())
cpassword = forms.CharField(label='Confirm Password',widget = forms.PasswordInput())
email = forms.EmailField(label='E-mail Address')
def clean(self):
if self.cleaned_data['cpassword']!=self.cleaned_data['password']:
raise forms.ValidationError("Passwords don't match")
return self.cleaned_data
class ProfileForm(forms.ModelForm):
phonenumber = forms.CharField(label='Phone Number')
class Meta:
model = UserProfile
exclude = ('user')
解决方法啊哈!您看到的验证错误消息实际上不是验证错误消息.让我解释.当使用as_p渲染模型窗体实例时,它将以下列方式呈现每个字段:<p><label ...>fieldname</label> <input ... name="fieldname" /> HELP TEXT IF ANY</p> 字符串必需. 30个字符以内.您在字段右侧看到的字母,数字和@ /./ / – / _字符只不过是帮助文本.这个帮助文本取自模型定义 – 您可以通过访问django / contrib / auth / models.py并检查User类的定义来验证这一点. 当您覆盖用户名字段时,您将省略任何帮助文本.当然,“错误”消失了. 为了验证这个理论,在你的主要方法中做以下几点. def main(request):
uf = forms.UserForm()
upf = forms.UserProfileForm()
print "User form is bound:%s errors:%s" % (uf.is_bound,uf.errors)
return render_to_response("authentication/index.html",{'form1': uf,'form2':upf})
更新 if self.cleaned_data['cpassword']!=self.cleaned_data['password']: 当用户不提供一个或两个密码和密码时,此行可能会导致麻烦.例如,尝试从Django shell: >>> data = dict(username = 'admin',cpassword = 'foo',email='admin@bar.com')
>>> f = RegisterForm(data)
>>> f.is_bound
True
>>> f.is_valid()
Traceback (most recent call last):
...
File "<pyshell#2>",line 8,in clean
if self.cleaned_data['cpassword']!=self.cleaned_data['password']:
KeyError: 'password'
更改表单的清洁方法,以确保在比较之前两个值都存在.这样的东西 def clean(self):
password = self.cleaned_data.get('password',None)
cpassword = self.cleaned_data.get('cpassword',None)
if password and cpassword and (password == cpassword):
return self.cleaned_data
else:
raise forms.ValidationError("Passwords don't match") (编辑:安卓应用网) 【声明】本站内容均来自网络,其相关言论仅代表作者个人观点,不代表本站立场。若无意侵犯到您的权利,请及时与联系站长删除相关内容! |
