Python3调用微信企业号API发送文本消息代码示例
发布时间:2020-05-24 16:02:47 所属栏目:Python 来源:互联网
导读:本文主要向大家分享了Python3调用微信企业号API发送文本消息示例的有关代码,具体如下:
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本文主要向大家分享了Python3调用微信企业号API发送文本消息示例的有关代码,具体如下:
#!/usr/bin/env python
# -*- coding:utf-8 -*-
import urllib.request
import json
import sys
import logging
touser = '@all'
agentid = 0
corpid = 'wx5aef2da956514535'
corpsecret = 'Co17m_OPlvE8Q4P2RKKwtq5oIA3p42xGUZEvCHBI8S0'
url = 'https://qyapi.weixin.qq.com'
subject = sys.argv[2]
message = sys.argv[3]
logging.basicConfig(level=logging.DEBUG,filename='E:Python_projectScriptsmy.log',format='%(asctime)s - %(levelname)s: %(message)s')
class Weixin:
def __init__(self,url,corpid,corpsecret):
token_url = '%s/cgi-bin/gettoken?corpid=%s&corpsecret=%s' % (url,corpsecret)
self.token = json.loads(urllib.request.urlopen(token_url).read().decode())['access_token']
def send_message(self,data):
send_url = '%s/cgi-bin/message/send?access_token=%s' % (url,self.token)
self.respone = urllib.request.urlopen(urllib.request.Request(url=send_url,data=data)).read()
x = json.loads(self.respone.decode())['errcode']
if x == 0:
logging.debug('Successfully %s %s' % (subject,message))
return 'Succesfully'
else:
logging.debug('Failed %s %s' % (subject,message))
return 'Failed'
def messages(self,subject,message):
values = {
"touser": touser,"msgtype": 'text',"agentid": agentid,"text": {'content': subject + message},"safe": 0
}
return self.send_message(url,bytes(json.dumps(values),'utf-8'))
if __name__ == '__main__':
obj = Weixin(url,corpsecret)
ret = obj.messages(subject,message)
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