python中的字典用法示例
发布时间:2020-05-24 23:40:16 所属栏目:Python 来源:互联网
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下面是脚本之家 jb51.cc 通过网络收集整理的代码片段。 脚本之家小编现在分享给大家,也给大家做个参考。 #!/usr/bin/env python
#
# [SNIPPET_NAME: Dictionaries 101]
# [SNIPPET_CATEGORIES: Python Core]
# [SNIPPET_DESCRIPTION: Basic and not so basic dictionary operations]
# [SNIPPET_AUTHOR: Bruno Girin <[emailprotected]>]
# [SNIPPET_LICENSE: GPL]
# This snippet demonstrates how the basics on dictionaries: how to create,add,# remove items,get items,iterate,etc.
#
# First,let's create simple dictionary. A dictionary (called map in Java hash
# in perl) is similar to a list with the difference that the key doesn't
# have to be an integer,it can be anything.
#
# A dictionary is enclosed in curly brackets and each key is mapped to its
# corresponding value with a colon. So in the dictionary below,we associate
# the key Karmic with the value 9.10 and so on for the 5 pairs.
#
print "Create a simple dictionary"
simpleDict = {"Karmic": "9.10","Lucid": "10.04","Hardy": "7.10","Jaunty": "8.10","Intrepid": "8.04"}
# print it
print simpleDict
#
# Another way to create a dictionary is to zip two lists containing the keys
# and values in the same order to create a list of tuples,which we can then
# pass to the dict() method to create a dictionary.
#
myKeys = ['Feisty','Edgy','Dapper']
myValues = ['7.04','6.10','6.06']
otherDict = dict(zip(myKeys,myValues))
print otherDict
#
# Interrogate the dictionary. It works exactly the same as with a list,with the
# exception that the key is no longer an integer.
#
print "nInterrogate the dictionary"
# get for value for key Jaunty
print simpleDict['Jaunty']
# get the length of the dictionary
print len(simpleDict)
# check if the dictionary contains the key Lucid
print 'Lucid' in simpleDict
print 'Breezy' in simpleDict
#
# Modify the dictionary
#
print "nModify the dictionary"
# add another item
simpleDict['Hoary'] = '5.06'
print simpleDict
# oops! let's sort this out by replacing in place
simpleDict['Hoary'] = '5.04'
print simpleDict
# update the dictionary with mappings from another one
simpleDict.update(otherDict)
print simpleDict
# remove an item from the list (Hardy should not be in the list anymore)
del simpleDict['Hoary']
print simpleDict
#
# Iterate over the dictionary. A dictionary doesn't enforce a natural ordering
# like a list but we can still iterate over it in multiple ways.
# However,note that when you iterate,the order in which the items are
# retrieved is unspecified.
#
print "nIterate over the dictionary"
print "nby keys"
for k in simpleDict.keys():
print k
print "nby values"
for v in simpleDict.values():
print v
print "nby items"
# note the syntax to retrieve the key and value at the same time
for k,v in simpleDict.items():
print k,'=>',v
#
# More interesting transformations from list to dictionary and vice versa.
# List comprehension allow you to do a lot of interesting stuff,in particular
# tranforming lists into dictionaries and the other way around.
#
print "nList to dictionary and vice versa"
# First,let's transform our dictinary into a list of tuples
simpleList = [(k,v) for k,v in simpleDict.items() ]
print simpleList
# Create a map from a list with the list's entry as key and the index as value
# This method takes advantage of another way of creating a map,using a
# sequence of tuples,so in practice,we create a tuple for each item in the
# list,create a list from all the tuples using a list comprehension and pass
# it as argument to the dict() function
cityList = ['London','Paris','New York','Tokyo']
cityDict = dict([(x,i) for i,x in enumerate(cityList)])
print cityDict
# Create a map from a number to its square
squareDict = dict([(x,x * x) for x in range(1,10)])
print squareDict
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