python – Django – 替换urlfield的部分

发布时间：2020-05-25 09:02:54 所属栏目：Python 来源：互联网
导读：我现在可以加载youtube的单个视频网址.但现在的问题是加载youtube的播放列表视频.所以我的问题是,如何替换两个相同的模式,但两者都有不同的网址替换？例如：实际网址：iframe width=400 height=327 src=http://www.youtube.com/embed/1UiICgvrsFIamp;lis
我现在可以加载youtube的单个视频网址.但现在的问题是加载youtube的播放列表视频.所以我的问题是,如何替换两个相同的模式,但两者都有不同的网址替换？
例如：
实际网址：
</pre>
<p>将图案替换为如下：</p>
<p></p>
<pre><code><iframe width="560" height="315" src="//www.youtube.com/embed/1UiICgvrsFI?list=PLvAOICvbvsbnc5dLG0YR9Mq_tFfzAhQSp" allowfullscreen&gt;</iframe&gt;
</code></pre>
<p>这里是第一个&amp; amp;改变？和第二个&amp; amp;并且剥离其以下内容,即&amp; amp; index = 1.</p>
<p>这是models.py：</p>
<p></p>
<pre><code>class Video(models.Model):
    title = models.CharField(max_length=100)
    video_url = models.URLField(max_length=100)

    def save(self,*args,**kwargs):
        new_url = (self.video_url.replace("watch?v=","v/"))
        super(Video,self).save(*args,**kwargs)
        if new_url:
            self.video_url = new_url
</code></pre>
<p>编辑：</p>
<p></p>
<pre><code>def save(self,**kwargs):
        new_url = re.sub('watch?v=','embed/',self.video_url)
        new_url = re.sub(r'^(http://)([wW]+)&amp;amp;list=([wW]+)(&amp;amp;index=[d]+)$',r'//2?list=3',new_url)
        if new_url:
            self.video_url = new_url
            super(Video,**kwargs)
</code></pre>

最佳答案
首先,似乎您的网址已经过编码.请检查您的模板中是否没有| urlencode过滤器(https://docs.djangoproject.com/en/dev/ref/templates/builtins/#urlencode).</p>
<p>要将视频网址更改为播放列表网址,您必须使用正则表达式.您可以创建一种方法,将视频网址转换为播放列表网址：</p>
<p></p>
<pre><code>import re
...
def playlist_url(self):
    """
    Generates a playlist URL
    """
    new_url = re.sub(r'^(http://)([wW]+)&amp;list=([wW]+)(&amp;index=[d]+)$',self.video_url)
    return new_url
...
</code></pre></p>                        <p style="text-align:right;">（编辑：安卓应用网）</p>
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