asp.net-mvc – 使用ViewModel的MVC 3动态表单
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我已经尝试了几个星期来关注如何创建动态表单的几个教程,使其能够在表单中添加另一个“成分”.这是我试图遵循的文章. http://www.joe-stevens.com/2011/07/24/asp-net-mvc-2-client-side-validation-for-dynamic-fields-added-with-ajax/ 现在我正在使用添加链接添加多个recipeIngredients,但是我需要在单击链接时同时添加“ingredientName”和“recipeIngredient”数量. 我甚至不知道从哪里开始修复这个,我不确定我是否应该使用viewmodel或者我是否会完全错误.这是我的数据库图http://i44.tinypic.com/xp1tog.jpg. 这是我的CreateView: @model ViewModels.RecipeViewModel
@using Helpers;
<h2>CreateFullRecipe</h2>
<script src="@Url.Content("~/Scripts/jquery.validate.min.js")" type="text/javascript"></script>
<script src="@Url.Content("~/Scripts/jquery.validate.unobtrusive.min.js")" type="text/javascript"></script>
<script type="text/javascript">
$().ready(function () {
$("#add-recipeingredient").click(function () {
$.ajax({
url: '@Url.Action("GetNewRecipeIngredient")',success: function (data) {
$(".new-recipeingredients").append(data);
Sys.Mvc.FormContext._Application_Load();
}
});
});
});
</script>
@using (Html.BeginForm())
{
@Html.ValidationSummary(true)
<fieldset>
<legend>Recipe</legend>
<div class="editor-label">
@Html.LabelFor(model => model.Recipe.RecipeName)
</div>
<div class="editor-field">
@Html.EditorFor(model => model.Recipe.RecipeName)
@Html.ValidationMessageFor(model => model.Recipe.RecipeName)
</div>
</fieldset>
<fieldset>
<legend>RecipeIngredients</legend>
<div class="new-recipeingredients">
@Html.EditorFor(model => model.RecipeIngredients)
</div>
<div style="padding: 10px 0px 10px 0px">
<a id="add-recipeingredient" href="javascript:void(0);">Add another</a>
</div>
</fieldset>
<div>
<input type="submit" value="CreateFullRecipe" />
</div>
}
<div>
@Html.ActionLink("Back to List","Index")
</div>
我对recipeingredient的editortemplateview: @model Models.RecipeIngredient
@using Helpers;
@using (Html.BeginAjaxContentValidation("form0"))
{
using (Html.BeginCollectionItem("RecipeIngedients"))
{
<div style="padding: 5px 0px 5px 0px">
@Html.LabelFor(model => model.Amount)
@Html.EditorFor(model => model.Amount)
@Html.ValidationMessageFor(model => Model.Amount)
</div>
}
}
我的控制器相关方法: [HttpGet]
public ActionResult CreateFullRecipe()
{
var recipeViewModel = new RecipeViewModel();
return View(recipeViewModel);
}
//
// POST: /Recipe/Create
[HttpPost]
public ActionResult CreateFullRecipe(RecipeViewModel recipeViewModel)
{
if (ModelState.IsValid)
{
db.Recipes.Add(recipeViewModel.Recipe);
db.SaveChanges();
int recipeID = recipeViewModel.Recipe.RecipeID;
for (int n = 0; n < recipeViewModel.RecipeIngredients.Count(); n++)
{
db.Ingredients.Add(recipeViewModel.Ingredients[n]);
int ingredientID = recipeViewModel.Ingredients[n].IngredientID;
recipeViewModel.RecipeIngredients[n].RecipeID = recipeID;
recipeViewModel.RecipeIngredients[n].IngredientID = ingredientID;
db.RecipeIngredients.Add(recipeViewModel.RecipeIngredients[n]);
db.SaveChanges();
}
return RedirectToAction("Index");
}
return View(recipeViewModel);
}
public ActionResult GetNewIngredient()
{
return PartialView("~/Views/Shared/IngredientEditorRow.cshtml",new Ingredient());
}
public ActionResult GetNewRecipeIngredient()
{
return PartialView("~/Views/Shared/_RecipeIngredientEditRow.cshtml",new RecipeIngredient());
}
我的视图模型: public class RecipeViewModel
{
public RecipeViewModel()
{
RecipeIngredients = new List<RecipeIngredient>() { new RecipeIngredient() };
Ingredients = new List<Ingredient>() { new Ingredient() };
Recipe = new Recipe();
}
public Recipe Recipe { get; set; }
public IList<Ingredient> Ingredients { get; set; }
public IList<RecipeIngredient> RecipeIngredients { get; set; }
}
}
如果有任何其他信息需要帮助解决我的问题,请告诉我.这真的让我发疯,所以我期待着能得到任何帮助 我还想提一下,控制器发布方法createfullrecipe是用于预定义的列表,当我不担心给用户添加另一种成分的能力时它起作用,而我只是默认表单有2种成分而我的观点有这注释掉了创建它们的代码.我真正想做的就是让viewmodel将表单数据传递给控制器,我可以像我的createfullrecipe控制器方法那样处理数据. @* @for (int n = 0; n < Model.Ingredients.Count(); n++)
{
<div class="editor-label">
@Html.LabelFor(model => model.Ingredients[n].IngredientName)
</div>
<div class="editor-field">
@Html.EditorFor(model => model.Ingredients[n].IngredientName)
@Html.ValidationMessageFor(model => model.Ingredients[n].IngredientName)
</div>
<div class="editor-label">
@Html.LabelFor(model => model.RecipeIngredients[n].Amount)
</div>
<div class="editor-field">
@Html.EditorFor(model => model.RecipeIngredients[n].Amount)
@Html.ValidationMessageFor(model => model.RecipeIngredients[n].Amount)
</div>
}*@
这是我的模型类: public class Recipe
{
public int RecipeID { get; set; }
public string RecipeName { get; set; }
public string Description { get; set; }
public int? PrepTime { get; set; }
public int? CookTime { get; set; }
public string ImageURL { get; set; }
public virtual IList<RecipeTag> RecipeTags { get; set; }
public virtual IList<Rating> Ratings { get; set; }
public virtual IList<RecipeStep> RecipeSteps { get; set; }
public virtual IList<RecipeIngredient> RecipeIngredients { get; set; }
}
public class RecipeIngredient
{
public int RecipeIngredientID { get; set; }
public string IngredientDesc { get; set; }
public string Amount { get; set; }
public int RecipeID { get; set; }
public int? IngredientID { get; set; }
public virtual Recipe Recipe { get; set; }
public virtual Ingredient Ingredient { get; set; }
}
public class Ingredient
{
public int IngredientID { get; set; }
public string IngredientName { get; set; }
public virtual ICollection<RecipeIngredient> RecipeIngredients { get; set; }
}
解决方法您的代码存在很多问题.我更喜欢一步一步地说明一个简化的例子,你可以适应你的需要.楷模: public class RecipeViewModel
{
public Recipe Recipe { get; set; }
public IList<RecipeIngredient> RecipeIngredients { get; set; }
}
public class Recipe
{
public string RecipeName { get; set; }
}
public class RecipeIngredient
{
public int Amount { get; set; }
[Required]
public string IngredientDesc { get; set; }
}
控制器: public class HomeController : Controller
{
public ActionResult Index()
{
var recipeViewModel = new RecipeViewModel();
return View(recipeViewModel);
}
[HttpPost]
public ActionResult Index(RecipeViewModel recipeViewModel)
{
if (!ModelState.IsValid)
{
// there wre validation errors => redisplay the view
return View(recipeViewModel);
}
// TODO: the model is valid => you could pass it to your
// service layer for processing
return RedirectToAction("Index");
}
public ActionResult GetNewRecipeIngredient()
{
return PartialView("~/Views/Shared/EditorTemplates/RecipeIngredient.cshtml",new RecipeIngredient());
}
}
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