从Asp.Net Webforms显示引导模式

需要建议,如何打开一个twitter bootstrap模态,从 Asp.net Webform代码背后？

我想根据保存时的一些要求打开模态.一旦用户点击保存按钮,它将以代码背后的方式运行验证,如果有任何验证错误,则在引导模态对话框中显示所有错误.这一切都应该发生在保存按钮单击.

我尝试下面的代码,但它提示我java脚本错误“错误：对象不支持属性或方法’模态’”.谢谢

Asp.Net Webforms 4.5

Bootstrap V3.0.1

jQuery的1.9.0.js

jQuery的UI,1.8.24.js

Default.aspx 

<asp:Content runat="server" ID="DisplayContent" ContentPlaceHolderID="DisplayContent">
<div class="container">
</div>
</asp:Content>

<asp:Content runat="server" ID="BodyContent" ContentPlaceHolderID="MainContent">

<div class="container">
    <div class="btn-group">
        <asp:Button ID="btnSubmit" class="btn-info" runat="server" Text="Submit"          
        OnClick="btnSubmit_Click"></asp:Button>
    </div>
</div>


<%--Bootstrap Modal Dialog--%>
<div class="modal fade" id="myModal" role="dialog" aria-labelledby="myModalLabel" aria-hidden="true">
    <div class="modal-dialog">
        <div class="modal-content">
            <div class="modal-header">
                <button type="button" class="close" data-dismiss="modal" aria-hidden="true">&times;</button>
                <h4 class="modal-title">Validation Errors List for HP7 Citation</h4>
            </div>
            <div class="modal-body">
            </div>
            <div class="modal-footer">
                <button class="btn btn-info" data-dismiss="modal" aria-hidden="true">Close</button>
            </div>
        </div>
    </div>
</div>
</asp:Content>


Default.aspx.cs

protected void btnSubmit_Click(object sender,EventArgs e)
{
  ScriptManager.RegisterClientScriptBlock(this,this.GetType(),"none","
 <script>$('#mymodal').modal('show');</script>",false);
 }



 Script order defined in master page

 <asp:PlaceHolder ID="PlaceHolder1" runat="server">
    <%: Scripts.Render("~/bundles/modernizr") %>
    <%: Scripts.Render("~/bundles/jquery") %>
    <%: Scripts.Render("~/bundles/bootstrap") %>
    <%: Scripts.Render("~/bundles/common") %>
</asp:PlaceHolder>

解决方法

<div class="container">
    <div class="btn-group">
        <asp:Button ID="btnSubmit" class="btn-info" runat="server" Text="Submit"          
        OnClick="btnSubmit_Click"></asp:Button>
    </div>
</div>


<!-- Bootstrap Modal Dialog -->
<div class="modal fade" id="myModal" role="dialog" aria-labelledby="myModalLabel" aria-hidden="true">
    <div class="modal-dialog">
        <asp:UpdatePanel ID="upModal" runat="server" ChildrenAsTriggers="false" UpdateMode="Conditional">
            <ContentTemplate>
                <div class="modal-content">
                    <div class="modal-header">
                        <button type="button" class="close" data-dismiss="modal" aria-hidden="true">&times;</button>
                        <h4 class="modal-title"><asp:Label ID="lblModalTitle" runat="server" Text=""></asp:Label></h4>
                    </div>
                    <div class="modal-body">
                        <asp:Label ID="lblModalBody" runat="server" Text=""></asp:Label>
                    </div>
                    <div class="modal-footer">
                        <button class="btn btn-info" data-dismiss="modal" aria-hidden="true">Close</button>
                    </div>
                </div>
            </ContentTemplate>
        </asp:UpdatePanel>
    </div>
</div>

并在CodeBehind中使用这个：

protected void btnSubmit_Click(object sender,EventArgs e)
{
    lblModalTitle.Text = "Validation Errors List for HP7 Citation";
    lblModalBody.Text = "This is modal body";
    ScriptManager.RegisterStartupScript(Page,Page.GetType(),"myModal","$('#myModal').modal();",true);
    upModal.Update();
}

您可以看到,首先设置您的Modal的标题和正文,然后显示它,然后更新UpdatePanel以显示Label的消息.
您可以在页面末尾添加您的模式代码,这是提高页面加载性能的好方法,也可以防止与其他UpdatePanels或元素的任何冲突.

更新：

如果您收到错误：对象不支持属性或方法’模态’,这可能是因为安装引导失败.
尝试使用原始引导示例来检查代码：
http://getbootstrap.com/javascript/#modals

如果您再次收到此错误,这些链接可能有帮助：

http://geekswithblogs.net/JeremyMorgan/archive/2012/09/18/how-to-use-twitter-bootstrap-on-an-asp.net-website.aspx

http://www.mytecbits.com/microsoft/dot-net/bootstrap-3-0-0-with-asp-net-web-forms

（编辑：安卓应用网）

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