如何使用asp.net和c#流式传输Excel 2007或Word 2007文件

我正在开发一个网络应用程序,需要流式传输各种文件.我可以做PDF,图像和较旧的Office文档.但是,当我尝试与2007年的文件,它打破了.这是我的代码：

Response.Buffer = true;
    Response.Clear();
    Response.ClearContent();
    Response.ClearHeaders();
    switch (FileExtension.ToLower())
    {
        case "pdf":
            Response.ContentType = "application/pdf";
            break;
        case "doc":
            Response.ContentType = "application/msword";
            break;
        case "docx":
            Response.ContentType = "application/vnd.ms-word.document.12";
            break;
        case "xls":
            Response.ContentType = "application/vnd.ms-excel";
            break;
        case "xlsx":
            Response.ContentType = "application/vnd.ms-excel.12";
            break;
        default:
            Response.ContentType = "image/jpeg";
            break;
    }
    Response.BinaryWrite(buffer);

我得到的错误是：

An invalid character was found in text content. Error processing resource 'http://DomainName/GetFile.aspx...

PK

有什么建议么？

解决方法

application/vnd.openxmlformats-officedocument.wordprocessingml.document
application/vnd.openxmlformats-officedocument.spreadsheetml.sheet

http://www.bram.us/2007/05/25/office-2007-mime-types-for-iis/

编辑：

以下简化示例适用于我.它与你的不同之处在于它使用通用处理程序而不是Web表单(这更适合于这样的东西).

要测试它,请确保应用程序的顶级文件夹中有一个名为Book1.xlsx的excel 2007文件.

DownloadSpreadsheet.ashx:

<%@ WebHandler Language="C#" Class="DownloadSpreadsheetHandler" %>

using System;
using System.Web;
using System.IO;

public class DownloadSpreadsheetHandler: IHttpHandler {

    public void ProcessRequest (HttpContext context) {
        context.Response.ContentType = "application/vnd.openxmlformats-officedocument.spreadsheetml.sheet";
        string path = context.Server.MapPath("~/Book1.xlsx");
        using (FileStream spreadsheet = File.OpenRead(path))
        {
            CopyStream(spreadsheet,context.Response.OutputStream);
        }
    }

    public bool IsReusable {
        get {
            return false;
        }
    }

    private static void CopyStream(Stream input,Stream output)
    {
        byte[] buffer = new byte[32768];
        while (true)
        {
            int read = input.Read(buffer,buffer.Length);
            if (read <= 0)
                return;
            output.Write(buffer,read);
        }
    }

}

（编辑：安卓应用网）

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