linux – 如何遍历Bash中的所有ASCII字符？

我知道如何迭代字母表：

for c in {a..z}; do ...; done

但我无法弄清楚如何遍历所有ASCII字符.有谁知道怎么样？

解决方法

您可以使用these函数执行此操作：

# POSIX
# chr() - converts decimal value to its ASCII character representation
# ord() - converts ASCII character to its decimal value

chr() {
  [ ${1} -lt 256 ] || return 1
  printf $(printf '%03o' $1)
}

# Another version doing the octal conversion with arithmetic
# faster as it avoids a subshell
chr () {
  [ ${1} -lt 256 ] || return 1
  printf $(($1/64*100+$1%64/8*10+$1%8))
}

# Another version using a temporary variable to avoid subshell.
# This one requires bash 3.1.
chr() {
  local tmp
  [ ${1} -lt 256 ] || return 1
  printf -v tmp '%03o' "$1"
  printf "$tmp"
}

ord() {
  LC_CTYPE=C printf '%d' "'$1"
}

# hex() - converts ASCII character to a hexadecimal value
# unhex() - converts a hexadecimal value to an ASCII character

hex() {
   LC_CTYPE=C printf '%x' "'$1"
}

unhex() {
   printf x"$1"
}

# examples:

chr $(ord A)    # -> A
ord $(chr 65)   # -> 65

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