使用SQL Server 2008表中的新值更新Xml属性

我在SQL Server 2008中有一个表,它有一些列.其中一列是Xml格式
我想更新一些属性.

例如,我的Xml列的名称是XmlText,它在5个第一行中的值如下：

<Identification Name="John"  Family="Brown"     Age="30" /> 
 <Identification Name="Smith" Family="Johnson"   Age="35" /> 
 <Identification Name="Jessy" Family="Albert"    Age="60" />
 <Identification Name="Mike"  Family="Brown"     Age="23" />
 <Identification Name="Sarah" Family="Johnson"   Age="30" />

我想更改30到40之间的所有Age属性,如下所示：

<Identification Name="John"  Family="Brown"     Age="40" /> 
 <Identification Name="Smith" Family="Johnson"   Age="35" /> 
 <Identification Name="Jessy" Family="Albert"    Age="60" />
 <Identification Name="Mike"  Family="Brown"     Age="23" />
 <Identification Name="Sarah" Family="Johnson"   Age="40" />

解决方法

update YourTable set
  XMLText.modify('replace value of (/Identification/@Age)[1] with "40"')
where XMLText.value('(/Identification/@Age)[1]','int') = 30

使用表变量的工作示例.

declare @T table(XMLText xml)

insert into @T values('<Identification Name="John"  Family="Brown"   Age="30" />')
insert into @T values('<Identification Name="Smith" Family="Johnson" Age="35" />') 
insert into @T values('<Identification Name="Jessy" Family="Albert"  Age="60" />')
insert into @T values('<Identification Name="Mike"  Family="Brown"   Age="23" />')
insert into @T values('<Identification Name="Sarah" Family="Johnson" Age="30" />')

update @T set
  XMLText.modify('replace value of (/Identification/@Age)[1] with "40"')
where XMLText.value('(/Identification/@Age)[1]','int') = 30

select *
from @T

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